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Thank you both for the tips. Bill I must admit that I only understood what you've tryed to describe after having seen the figure at the site that Juha reported. http://www.uta.edu/optics/research/ellipsometry/ellipsometry.htm >Fig. 2 Schematic of the geometry of an ellipsometry experiment. >The coordinate system used to describe the ellipse of polarization is the p-s >coordinate system. The s-direction is taken to be perpendicular to the >direction of propagation and parallel to the sample surface. The p-direction >is taken to be perpendicular to the direction of propagation and contained in >the plane of incidence. So in order to make things easier for me ;-) lets simulate my case. I've conducted a polarized IR-transission experiment using a thin film. Try to imagine how fig 2 would be if theta was equal to zero s and p would lie on the surface of the sample and would have north-south and east-west ?true? So you wanna say that whenever I see a polar diagram of p- or - polarization at various angles concerning a thin film ir-trasmission exp. the different angles refer to theta(fig2) as a tilt angle. I guess that at theta =0 -or at whatever theta- in order to have s- or p- light I just turn the polarizer 90 degres. If I'm not true please tip me on how can i get p- or s- polarized light (using a polarizer). Maybe my first message was toooo bad formed but the above was what I was trying to state. In the film that I've used I have oriented dipoles and believing that there was only one p- or s- state I kept wondering "how can I find polar diagrams of them"????????? It's now more than obvious that the p-polarized (and s-)modes are infinite as the values that theta angle can have. thanks for everything, greetings spiros
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