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Fred, Thanks a lot for your kind reply. } Briefly, MeOH has a lower proton affinity than (say) acetonitrile. This } means that MeOH2+ is a stronger proton donor than CH3CNH+, so you will } generally see more abundant ions using MeOH as HPLC solvent, compared to } CH3CN, for certain types of analyte. If the analytes have higher proton affinity than MeCN and interference have proton affinity between MeOH and MeCN, we can get rid of or reduce the interference peak and ionization suppression by using MeCN (in + mode). Is it true? MeCN has higher proton affinity that MeOH. Would that mean that MeCN would work better than MeOH in - mode (the opposite of the above, more ionization for difficult to ionize molecules)? Thanks in advance. Jimmy
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