Re: The need of geodesics in physics

In <[EMAIL PROTECTED]>, on 10/31/2003
   at 09:05 AM, [EMAIL PROTECTED] (Ken S. Tucker) said:

>but QT requires m to change discretely, 

No. QT allows both discrete and continuous spectra. Further, even in
systems with discrete spectra, QT is based on differential equations
involving continuous variables. The Devil is in the details; you can't
understand what is going on in QT by reading a popularization.

>changing orbits

That would be the old QT, obsolete even before QED came along.

-- 
     Shmuel (Seymour J.) Metz, SysProg and JOAT

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