Re: Charge without rest mass

On 2 Dec 2003, Squark wrote:

> Ok, so it's not spontaneous symmetry breaking. The later would give
> Cexp(-r/r0)/r^2. I guess another way to put it is that we get no IR
> fixed point?

No, we would get a non-interacting infrared fixed point, the fine
structure constant would flow to zero.

> It should vanish since m/e = 0 :-)

Nope, you got the factor in the opposite way. The Lorentz force is
q ( E + v x B ). Note the term (v x B), not (p x B). It is
relativistically extended to q.v_{mu} F^{mu,nu} where "v" is a unit
4-vector. For massless particles, v^{mu} has essentially infinite
coordinates because it is p/m where p is finite and m is zero.

The force is really becoming infinite, not zero. I wrote that what you
wrote - p x B - is "m/e" times the correct Lorentz force, not the other
way around. ;-) Your (p x B) is finite for massless particles, but the
true Lorentz force is e/m times bigger - i.e. infinite if "p" is kept
finite.
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