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[EMAIL PROTECTED] (Ken S. Tucker) wrote: > >The quantity T is identitied as the stress tensor of the system, > >and e as the system's internal energy. They are related by: > > 1/2 trace(T) = rho e. > > > >In fact, this is true for monoatomic gases. For diatomic and > >polyatomic gases, there is an additional component to e that > >does not arise from the 1/2 the trace of T. > > Agreed, would you say these "additional components" > are antisymmetric and or nonorthogonal components > off the trace, where the trace T solves only mono's? e and trace(T) are invariant under Galilean transformations, and under the "scale" or "additivity" transformation. So, the difference (e - 1/2 trace(T)) persists at all levels: microscopic and macroscopic, and is intrinsic. So, if the continuum decomposes into fundamental subsystems (the "particles") the difference (e - 1/2 trace(T)) for that subsystem represents a source of energy arising from intrinsic degrees of freedom OTHER than the translational degrees. It's direct evidence of the existence of non-translational degrees of freedom in particles (i.e., spin); and is entirely non-classical in origin. In fact, for polyatomic gases, the e WILL actually be 1/2 trace(T) at low enough temperatures; because the other degrees of freedom are frozen out. For diatomic gases, it pushes up to 5/6 trace(T) past a certain critical temperature, as the other degrees of freedom "thaw" out; and for polyatomic gases, up to trace(T).
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