Re: Force on an asymmetrical conductor

>"Lord Snooty ", answering my remark that the sum total of forces is J x B =
0.
> > The bottom wire is coated, so experiences mu times the field
> > experienced by the other 3 sides.  You did read my problem spec. didn't
you?

> No, I didn't. It's irrelevant.  If the field is really constant, nothing
will "fly" in it.

Well then you're missing the whole point of the device. The field isn't
constant.
Instead of a coating, you can imagine one side of the square loop being
screened.
In any case, we arrange so that one of the 4 sides experiences a different
B-field.

-Andrew