Re: Need help with solution: SL Dixon's Text

Thank You!  Yes I saw the reference to Eqn 7.11, but tried using 7.11a
as 1/[pi*Po1*ao1^3] where ao1 = sqrt(gamma*R*To1).
I appreciate your help!  Thanks again.

David

"Pete K." <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>...
> Did you miss the reference to Eqn 7.11?  The LHS of the eqn is
> mdot*Omega^2/[pi*k*gamma*Po1*sqrt(gamma*R*To1)].  If you take out
> mdot*omega^2/k, what's left,
> 1/[pi*gamma*Po1*sqrt(gamma*R*To1)], is equal to 0.6598e-8.  Did you actually
> try to plug in numbers?
> 
> Pete K.
> 
> "David Walden" <[EMAIL PROTECTED]> wrote in message
> news:[EMAIL PROTECTED]
> > A solution to problem 7.4 in SL Dixon's Fluid Mechanics and
> > Thermodynamics of Turbomachinery 4th Ed. has me stumped and I would
> > appreciate any help understanding the steps that were left out.
> >
> > "The compressible flow relation between mass flow rate, speed of
> > rotation and the flow parameters at the eye tip is given by eqn.
> > (7.11),
> >
> > 0.6598 x 10^-8 x (mdot x rads ^2)/k = ..."
> >
> > I've not figured out yet how we're to get 0.6598 x 10^-8
> >
> > Thanks for your time,
> >
> > David