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> Note to Walala: > > Lena, who is not really a blockhead (she is still very attractive in > advancing age), looks better interpolated. I divided each square into > four smaller ones, and made a new image in which each new square is the > weighted average of those around it. I used this set of weights: > > 1 2 1 > 2 4 2 > 1 2 1 > > Divide the sum by 16, of course. Other weightings may be better: I > pulled these out of a hat. > Cool, how did you get it? You are exactly right! That image is a residual error image or difference image after I process Lena blindly(or magically)... Now I understand it has a good correlation with "weighted average"... interesting! thanks a lot! -Walala
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