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> The very un-scientific method. "Trial and error". )-: What is known, however, > is that the statistics of wavelet high-passes is typically a "long tail > symmetric" function centered around the origin. This naturally asks for a > reconstruction point set off towards zero. There are even some model- > distributions that would allow you to compute *where exactly* the reconstruction > point would have to be. The reason why we choose 3/8th and not the precise > minimum was very simple: The 3/8th solution is quite easy to implement in > fix point. (*3, shift right three bits). > Dear Prof. Thomas, Thanks a lot for your answer! I still am not quite sure about your mechanism about the 3/8th bin? Can you give me some more detailed explanations on how you do that? For normal JPEG decoding, it is quite simple: just let's say we have quantized and rounded coefficients Y, which is a 8x8 matrix... We just need to element-wise multiply it with Q matrix, then take IDCT... So X=IDCT2(Y.*Q) That's all, very simple! But now with your 3/8th scheme, do we do X=IDCT2((Y-3/8).*Q) ??? I know this is come from Laplacian assumption of DCT coefficients... but I just don't know how to do it in practice... Thanks a lto, -Walala
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