Re: stress vs. strain determines crack limit

[EMAIL PROTECTED] (dave martin) wrote in message news:<[EMAIL PROTECTED]>...
> "seferiad" <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>...
> ....
......
> The first test I described (the constant deflection rate test) yields
> data that are easily compared with weibull predictions. (force
> observed)/(force predicted) is the fraction of surviving fibers and
> (engineering strain)*(initial modulus)*time/(initial number of fibers)
> is the fiber stress.

The last equation should be:
(fiber stress)=(engineering strain)*(initial modulus)/(initial number of fibers)

I'm sorry for the typo.