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"Pim" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > The ship is a stealth ship. > the side of the ship is flat. > As far as i understand this will result in radar reflection of the side of > the ship, but not to the sender of the radarwaves. > The radar waves are reflected at the same angle (in opposite direction) as > they have been send. > If you send waves to a flat wall not exactly directed towards you the wave > will not reflect back to you. > The side of the ship acts as a mirror to light. when you shine your torch to > the mirror you will not be illuminated, (unless the mirror is directed > exactly perpendicular to you. a deep dint in the mirror will destroy this > effect, the dint will ilumnitae in all directions. > (just as you will see a crack in your car window when it is illuminated > directly by the sun.) > I presume the whole of the ship isn't stealthy. You will have structures on deck which will "reflect" nicely - radomes, masts etc. In any case, depending on the sensitivity of the radar you may not "see" this hole. Radars will get reflections off the sea surface (sea clutter) which are likely to be larger in RCS than the cavity. If the radar can perform Doppler processing then you may separate out cavity returns from the sea clutter if the Doppler from the Cavity region is much greater than the Doppler of the sea surface. If you're looking near side on to the ship then the Doppler of the cavity will be small and you're likely to be masked by the sea clutter returns. Cheers, Carlos
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