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Re: How to measure inductance indirectly?





I have several inductors I'd like to know the values of. I have no way to measure L directly, ie, with a meter.

I've got a scope and signal generator. Is it as simple as hooking a known value of C in series with the L and sweeping the frequency range looking for a peak in V (accross the inductor) and a drop in I?


Not really- it depends on what the application is. If for example the inductors are for a switching power supply application, then you would want to measure the current response to a step voltage at various levels of DC bias- inductance is inferred from rise time L/R. If the inductors are to be used for RF or some other linear application where Q might be of interest then a simple technique is to use the Hay bridge at the application frequency:


Please view in a fixed-width font such as Courier.

Hay Bridge


+-----------+-----------------------------------+ | | | | \ _ \ | R1 / /| R3 / | \ \ | // / | | _ | | | /| | | C1 === +------------------------------+ --- /| | +-----+ | / \ | )|( | | | ~ | sig | )|( | | \ / gen | )|( === | --- | | | | | | +----+ | sd | +------+ | | +-|>|-+-/\/\-+-> VOM | | | \ | | ) \ | R2 / | === Lx ) Rx / | \ | detector | ) \ | / | | ) / | | | | | | | | | | | | +-----------+------+------------+---------------+------+ | | --- ///


Adjust R1 C1 for null at operating w=2pif where:



(R1-j/(wC1))(Rx*jwLx)=R2R3(Rx+jwLx)



Lx => Rx* -- = R2R3Rx or Lx=C1*R2*R3 C1


and


                                    R2*R3
         => R1RxwLx=R2R3wLx  or Rx= -----
                                     R1

            Rx
         Q= ---
            wLx




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