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On Wed, 26 Nov 2003 16:05:14 +0000, Richard Herring wrote: > In message <[EMAIL PROTECTED]>, Ernst Lippe > <[EMAIL PROTECTED]> writes >>On Tue, 25 Nov 2003 17:06:24 +0000, Richard Herring wrote: >> >>> In message <[EMAIL PROTECTED]>, Ernst Lippe >>> <[EMAIL PROTECTED]> writes >>> [...] >>> >>>>Normally, when people are talking about "the entropy of a source" what >>>>they mean is the entropy of the best possible statistical model of >>>>that source. >>>> >>>>Perhaps, some examples will make this clearer. Suppose that you >>>>have an entropy (bit)source, for which you can show that it is unbiased >>>>and that successive bits are independent. The best model for this >>>>source is a binomial distribution with p= 0.5. The entropy from >>>>this model is 100%, every output bit contains 1 bit of entropy. >>>> >>>>Now let's take the bits in the value of pi. When you assume that the >>>>best model is again the binomial distribution, the entropy in these >>>>bits is again 100%. However, when you assume that the best statistical >>>>model is the binary expansion of pi, you can always predict the next >>>>bit, so the entropy under this model is zero. >>> >>> If pi is normal, this is true for _any_ sequence of bits ;-) >>> >>> Finding the starting point is left as an exercise for the reader. >> >>The total entropy of any PRNG is equal to the amount of information >>in its parameters. In this case the only parameter is the starting >>point. Because the total entropy for any PRNG is fixed, the average >>entropy per output bit will always go to zero when you take longer >>output sequences. > > Of course. But who mentioned a PRNG? "Binary expansion of pi" is the > model, not the generator. Oh, now I see what you mean. Still your statement is a bit imprecise it is only true for finite sequences. greetings, Ernst Lippe
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