Re: Intersecting Sets Of Fitness!Q

John Edser wrote:
>>>BOH:- 
>>>>From the first site:
>>>"Given two sets A and B, the intersection of A and B, written A INT B, 
>>>is the set C of all elements that are in both A and B."
>>>>From the second site:
>>>"A INT B: A intersection B is the set of all elements that are in both 
>>>sets A and B."
>>>>From the third site:
>>>"Intersection - Denotes the set of elements that are members of all the 
>>>sets under consideration."
>>>(I've written INT for the intersection symbol, as it doesn't appear in 
>>>ASCII).
>>
> 
>>>JE:-
>>>Only _equivalent_ set elements are in n set
>>>intersections and not "the same" set element.
>>
> 
>>BOH:-
>>Having given you the quotes, I was hoping you would actually comment on 
>>them, rather than continue on about equivalence.  It's simply not a 
>>matter of whether elements are equivalent - it's whether a matter of 
>>which sets that are members of.
> 
> 
> <snip>
> 
>>JE:-
>>I have commented on the quotes, in detail.
>>For example, "set C of all elements that 
>>are in both A and B" means that all the
>>set elements in the intersection C are strictly
>>_equivalent_ elements and not just elements
>>from one set, i.e not "the same" elements.
> 
> 
> BOH:-
> This is opaque to me.  Are you saying that the elements in the 
> intersection C are not also in sets A and B?
> 
> JE:-
> The concept of equivalence is simple.
> Two things may be defined equivalent.
> This does not make them the one, same,
> thing, but it does mean either of them
> can represent the other. All I am saying 
> is that the elements in intersection C are equivalent
> set elements to the set elements in set A and B.
> 
Now can you answer my question - are you saying that the elements in the 
intersection C are not also in sets A and B?

Bob

-- 
Bob O'Hara

Rolf Nevanlinna Institute
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