
www.Usenet.com
| <-- __Chronological__ --> | <-- __Thread__ --> |
[Mod. note: the post below required substantial reformatting to fix up
MIME-encoding of line breaks and special characters; I hope I haven't
broken any of the equations in the process. Please try to post in
plain ASCII if possible, using TeX notation where necessary -- mjh]
[EMAIL PROTECTED] wrote:
> Rather than following Usenet convention and replying point by point
> (which would make for a long and unwieldy post that no one would
> want to slog through), I'll try to summarize where we disagree
> and explain my position reasonably succinctly. Please let me know
> if you think I've omitted an important facet of the discussion or
> misrepresented your position in any significant way.
In my opinion your examples are quite misleading, and some
simple calculations, using the Narlikar paper, can make things
much clearer. I will explain further below.
> Everyone agrees on the following:
>
> A comoving observer who looks at a comoving object in an expanding
> FRW spacetime will observe that object to be redshifted.
>
> I would like to defend the following proposition:
>
> A. If the distance between observer and observed is much less than the
> scale of spacetime curvature, then it makes sense to describe that
> redshift as a Doppler shift.
If this means "Doppler shift in flat space-time", I disagree.
See below for justification.
> (Here "scale of spacetime curvature" means either the horizon
> distance or the radius of spatial curvature, whichever is smaller.
> I labeled this proposition A because I want to compare it later with
> another proposition, which I'll call B.)
Using eqs. (19)-(21) of the Narlikar paper some simple
calculations give the norm V of the 3-velocity (obtained from
the parallely transported 4-velocity of the sender )as seen
from the observers local inertial rest frame:
[a^2(t_o)/a^2(t_s)]-1
V = ---------------------------- c (1)
[a^2(t_o)/a^2(t_s)]+1
where a(t) is the scale factor and the subscripts stand for
"observer" and "sender", respectively. (I do not use c=1 as
is done in the paper.) Notice that that V depends on a^2
rather than a.
When t_o - t_s is small we can write a(t_s) as a
Taylor expansion and neglect higher order terms
a(t_s) = a(t_o) + [\dot a (t_o)](t_s - t_o) + higher order terms. (2)
Inserting (2) into (1) then yields
\dot a (t_o)
V \approx --------------(t_o - t_s)c \approx H_0(t_o-t_s)c = H_0d (3)
a(t_s)
where d is the distance _in the tangent space-time_ (i.e. flat
space-time) at the observer.
From this we see directly that whereas V is approximately a
3-velocity given from the Hubble law in the tangent space-time
at the observer, there is no natural way to get V from the
properties of flat space-time itself. Rather, in a flat
space-time interpretation one has to pretend that V is
obtained operationally by parallel-transporting the 4-velocity
of a fictious sender located in the tangent space-time.But
this is not how V is obtained, and any interpretation besed on
this is rather dubious. On the other hand, if the sender is
not comoving, it makes sense to interpret his _peculiar
velocity_ as a ordinary 3-velocity in flat space-time since
the effect of curved space-time on parallel transport may be
neglected over small enough distances. (Note that the
relationship between peculiar velocities is not affected by
parallel transport in curved space-time.)
One may do exactly the same reasoning in Schwarzschild
space-time; see below.
> Let me make a few general observations first.
>
> - I'm not saying anything the least bit nonstandard about any actual
> measurements. That is, you and I would actually calculate the
> redshift in the same way. If I'm saying anything nonstandard at
> all, it's only about which ways to wrap words around the calculation
> are valid.
Right.
> - The observed redshift is a coordinate-independent quantity (like all
> observed quantities), but the act of interpreting that redshift as
> a Doppler shift is a coordinate-dependent act. That's not the least
> bit surprising: interpretations are often coordinate-dependent
> things.
Interpretations should also be made coordinate-independent as
much as possible.
> Now let me try to explain what I mean with an example. Suppose
> I stand on top of a tall tower and drop a baseball out. I track
> it with a radar gun as it falls to measure its speed. I claim
> the following:
>
> B. If the ball travels a distance that is small compared to the
> curvature scale of spacetime in my neighborhood, then it makes
> sense to interpret the observed redshift as a Doppler shift.
If this example is meant to be an analogy to the first one,
I claim that it is quite misleading. To have analogous
examples one should consider hovering observers in
example B, or allow for non-comoving observers in
example A.
So let us use eqs. (28)-(30) of the Narlikar paper
and find V for two hovering observers in Schwarzschild
space-time. Some simple calculations yield
1 - exp[v_s - v_o]
V = ------------------------ c (4)
1 + exp[v_s - v_o]
where
2MG
exp[v(r)] = 1 - ------------- (5)
c^2 r
For small v_s (equiv v(r_s)) we can express it via a Taylor
expansion and neglect higher order terms
v_s = v_o + v'_o(r_s - r_o) + higher order terms. (6)
Inserting (5) and (6) into (4) we then get
MG(r_o-r_s)
V \approx 0.5(v_o - v_s) \approx -------------- \approx H_od (7)
c^2 r_o^2
where d is the distance in the tangent space-time at the observer, and
MG
H_o \equiv ---------- (8)
c^2 r_o^2
is a "formal Hubble parameter" at r_o.
Again, just as for the FRW models, V may be seen as a 3-velocity
given from a local Hubble law in the tangent space-time of the
observer. And again there is no natural way to get V from
operations performed in the tangent space-time. Furthermore,
any interpretation of V as a recessional velocity in flat
space-time is obviously absurd. Yet this interpretation has
exactly the same mathematical justification as the
interpretation of cosmological recessional velocities. The only
difference is that cosmological space-times appeal much better to
an intuitive sense of "flat space-time" than the Schwarzschild
space-time does.
> The observed redshift will include a gravitational redshift as well
> as a Doppler shift, of course, but the latter will be very tiny
> under the assumed conditions; calling the observed redshift
> a Doppler shift is a kick-ass approximation.
Any spectral shift in GR may be interpreted as a generalized
Doppler shift in curved space-time. It is the interpretation in
terms of flat space-time which gets misleading; see above.
> Personally, I have a hard time imagining anyone disagreeing with
> proposition B. If you do disagree with it, then you're much more
> of a purist than I am: it seems to me that that would pretty
> much mean that you aren't willing to take any sort of
> Newtonian limit of general relativity. Anyway, if that is your
> point of view, then I don't really want to argue about it; I'm
> happy to agree to disagree.
I'm no "purist". However, when forming opininions regarding
geometrical models, I prefer that my understanding is based
on geometry as far as possible. One example of this is what
the unified model of spectral shifts makes so clear; namely their
geometrical relation to curved space-time. On the other hand
I find your position to be a little unclear and confused. For
example, the geometrical properties we are discussing has
nothing whatsoever to do with taking Newtonian limits.
> If, on the other hand, you accept proposition B but reject proposition
> A, then I'd like to know why. I think that they stand on *exactly*
> the same logical footing. In both cases, the following are true:
They do not; see above.
> I honestly don't understand how statements A and B differ in their
> "acceptability," so if anyone thinks that B is acceptable but A
> isn't , I'd love to hear why.
I recommend studying the examples I gave (and writing out the
calculations, it that would help).
| <-- __Chronological__ --> | <-- __Thread__ --> |