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The catenary assumption would not be valid for a piano string. It is far too short, stiff and under high tension; not to mention that it is confined at its ends. It's vibration would be calculated using beam formulas. A vertical string would not form itself into a catenary anyway; it would be a straight line*. Since gravity would have virtually no effect on a vertical string's vibration and there seems to be no appreciable difference in grand versus upright sustain times for equal length strings, I think we can safely assume that gravity has a negligible effect on sustain. Don *well, I suppose that one could argue that it is a special case of the hyperbolic cosine formula, but that's getting a little pedantic. "james" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > In article <[EMAIL PROTECTED]>, > Don A. Gilmore <[EMAIL PROTECTED]> wrote: > > >gravity. One might argue that gravity acting on the strings of a grand > >should change their timbre, but it would probably be indescernible since > >uprights don't have this lateral gravitational pull. > > But, does gravity affect sustain? With a uniform grav force, the string > can be represented as a catenary, regardless of the orientation. That's > as far as I get setting up the problem... > > > >
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