
www.Usenet.com
| <-- __Chronological__ --> | <-- __Thread__ --> |
"Rich Stowell" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] > Most things in aviation are related to the wings-level, 1-g stall > speed, Vso. The maneuvering speed, Va, is actually the stall speed of > the airplane at the design limit, and it is related to Vso by the > square root of the g-load. (Of course, all of these are CAS, so you > may have to do some massaging through the airseed calibration data to > convert back and forth between IAS and CAS to find the numbers you > must read on the airspeed indicator.) > > For example, in aerobatic airplanes like the Citabria which were > certificated at +5.0 g's (at max. gross), Va = 2.24 x Vso. In > aerobatic airplanes certificated at +6.0 g's (at max. gross), Va = > 2.45 x Vso. > > In terms of the snap roll entry speed (and snap rolls are really > accelerated stall/spins), the speed will naturally fall somewhere > between Vso and either 2.24 or 2.45 x Vso. > > In Eric Muller's book, Flight Unlimited, he recommends intially > practicing snap rolls at 1.5 x Vso, so there's a starting point. In my > experience, I'd recommend around 1.6 x Vso as a good "recommended" > snap roll speed, which translates into a 2.5-g pull to stall/spin the > airplane at that speed. The MAXIMUM snap roll speed should probably be > no greater than about 1.7 to 1.8 x Vso... > > Hope this helps (and HI Ken!), > > Rich > http://www.richstowell.com Don't forget that the structural g limit is for a symmetrical stall and is reduced to 2/3 for an asymmetric stall - therefore the absolute max snap roll speed at MAUW for a 6g airframe is 2xVso. Also, this speed should decrease at lighter weights by the ratio of the square roots of the weights. Vso at weight w = Vso x sqrt(w)/sqrt(MAUW), this can make a 10% difference to Vso so could easily affect the max snap speed by 10kts or more. Dave Sawdon
| <-- __Chronological__ --> | <-- __Thread__ --> |