Re: Bitwise Complement Question

FYI Here is the example which returns the incorrect result 
(for the last printf statement (~x)....

#include <stdio.h>
main()
{
        int x, y, z;

        x = 4321;
        y = 5678;


        printf("Given x = %u, i.e., 0X%04X\n", x, x);
        printf("      y = %u, i.e., 0X%04X\n", y, y);

        z = x & y;

        printf("x & y returns: %6u, i.e., 0X%04X\n", z, z);

        z = x | y;

        printf("x | y returns: %6u, i.e., 0X%04X\n", z, z);

        z = x ^ y;

        printf("x ^ y returns: %6u, i.e., 0X%04X\n", z, z);

        printf("   ~x returns: %6u, i.e., 0X%04X\n", ~x,~x);

        return 0;
}


Steven B wrote:
> I am a total beginner at C programming, and while following an example 
> of using the bitwise complement operator, I got a very different result 
> from that listed in the book.
>
> The example shows the bitwise complement of integer x, (dec value 4321) 
> as being 61214, hex value 0XEF1E. When I compile and run the example, I 
> end up with the dec value 4294962974, hex value 0XFFFFEF1E.
>
> The exercise includes examples of the other bitwise operators, all of 
> which return the same results as the book when I run it.
>
> I should mention that the book seems to lean towards Borland running on 
> Windows -- I am using GCC 3.2.2 on RedHat. Is there something I should 
> be learning about byte ordering or some such? I can't just ignore the 
> problem and move on because I really want to understand whats going on, 
> rather than just learning by rote.
>
> Thanks for any insight.