Re: function overloading

"Kuznetsov Dmitriy" <[EMAIL PROTECTED]> skrev i en meddelelse
news:[EMAIL PROTECTED]
> Hi all, can anybody explain to me why compiler choose 'void take_str
(char*
> str)' to call
> in next program.
>
> #include <iostream>
>
> void take_str (char* str)
> {
>   std::cout << "char*" << std::endl;
> }
>
> void take_str (const char* str)
> {
>   std::cout << "const char*" << std::endl;
> }
>
> int main(int argc, char* argv[])
> {
>   take_str ("const char*");
>   return 0;
> }

Hi Kuznetsov

This is because "const char*" (your string) is a char* and not as char
const*. This is nonintuitive of course, but C had it that way and it has
been preserved for compatibility.

Kind regards
Peter



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