Re: How to use IBURG to exchange tree nodes?

Alan Jiang <[EMAIL PROTECTED]> wrote:
> For example: (all variables are int type)
> a-c+d  is expressed as tree (a-c)+d, but I hope IBURG can transform it
> [..]
> Does it possible for IBURG rules to do the above job? Or it is just
> above the ability of IBURG?

IBurg can do it, but it is an unusual application of IBurg.
Typically, IBurg matches part of a tree and generates code for it in a
different representation. You could generate a new tree but you can't
re-write the tree that you are matching in place (at least I believe
so).

-- Christian