Re: a/sqrt(x)

"t0ny" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> hi,
>   i need to compute a/sqrt(x) in floating point arithmetic.
> if this is done using reciprocal square root, does it introduces
> errors .. if all operations are done with 'infinitely precise rounding'
> and same no of bits in fractional part?
> if yes .. how much precise Rsqrt(x) shud be to do this properly?

The rounding might be different, but it shouldn't be any more in error.

If you are that worried about error, maybe you shouldn't be using floating
point?

-- glen