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Parth wrote: > Wayne Rasmussen <[EMAIL PROTECTED]> wrote in message news:<[EMAIL PROTECTED]>... > > "Randolph M. Jones" wrote: > > > > > Parth wrote: > > > > the game is as follows: > > > > > > > > Agent 2 > > > > > > > > C D > > > > ________________ > > > > | | | > > > > C | 3, 3 | 1, 5 | > > > > |_______|_______| > > > > Agent 1 | | | > > > > D | 5, 1 | 0, 0 | > > > > | ______|_______| > > > > > > > > > > > > The game is to be played 1000 times against another agent... No fixed > > > > strategy seems to work against all other fixed stategies... suggest > > > > some cooperative mixed strategy for this game please. > > > > > > For extra credit, name this famous dilemma. > > > > > > Is this homework from your philosophy class or your AI class? > > > > Prisoner's dilemma. I remember that the tit-for-tat algorithm was best > > (back in the 80's) if you didn't know the exact number of turns. IIRC, > > someone had a slightly better than the tit-for-tat but can't recall the > > details. But the contest is fair when you play against all the other > > agents (one at a time) for the 1000 times then total the scores for all the > > runs. If someone has a bad agent and you are stuck against him, you could > > be screwed. So everyone has to play everyone else. > > > > Now if the teacher has his own code for the other agent, he is likely using > > tit-for-tat. If you know for sure that exactly 1000 times is used, then on > > the last one you play D instead of C. > > No the game is not prisoners dilemma... the payoff of 1 in the matrix > cells - [0][1] and [0][1] make it different from prisoners dilemma. It is the prisoners dilemma. Show me a credible source, other than yourself, that this is not a problem of that class.
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